page is in editing mode
Given:
Area = 528 m²
Length = 1 more than twice the breadth
Let the breadth be x m
⇒ Length = 2x+1 m
Area = Length × Breadth
(2x+1)(x)=528⇒2x2+x=528⇒2x2+x−528=0
✅ Quadratic Equation:
2x2+x−528=0
Let the first integer be x
⇒ Next consecutive integer = x+1
Product:
x(x+1)=306⇒x2+x=306⇒x2+x−306=0
✅ Quadratic Equation:
x2+x−306=0
Let Rohan's present age be x
⇒ Mother's age = x+26
After 3 years:
Rohan = x+3
Mother = x+26+3=x+29
Product of their ages:
(x+3)(x+29)=360⇒x2+32x+87=360⇒x2+32x−273=0
✅ Quadratic Equation:
x2+32x−273=0
Let the speed of the train be x km/h
Time = Distance ÷ Speed
Actual time = 480x
New speed = x−8 km/h
⇒ New time = 480x−8
Given:
New time=Actual time+3⇒480x−8=480x+3
Multiply through by x(x−8):
480x=480(x−8)+3x(x−8)⇒480x=480x−3840+3x2−24x⇒0=3x2−24x−3840⇒x2−8x−1280=0
✅ Quadratic Equation:
x2−8x−1280=0
Let me know if you'd like step-by-step solutions for these equations!